Question 1179558
**1. Finding the Lower Quartile**

First, we need to order the data from least to greatest:

37, 52, 56, 92, 107

The lower quartile (Q1) is the median of the lower half of the data.  Since we have an odd number of data points, we don't include the median of the whole set when finding the lower half.

Lower half: 37, 52

The median of 37 and 52 is **52**.

**Therefore, the answer is B. 52**


**2. Finding the Upper Quartile**

The upper quartile (Q3) is the median of the upper half of the data.

Upper half: 92, 107

The median of 92 and 107 is **99.5**.  (We would normally take the average of the two numbers, but since there are only two numbers in the upper half, the upper quartile is just the average of those two numbers.)

**Therefore, the answer is none of the above. The upper quartile is 99.5.**


**3. Finding the Average of the Lower and Upper Quartiles**

We found the lower quartile (Q1) to be 52 and the upper quartile (Q3) to be 99.5.

Average = (Q1 + Q3) / 2 = (52 + 99.5) / 2 = 151.5 / 2 = **75.75**

**Therefore, the answer is none of the above. The average is 75.75.**