Question 1181382
Here's the breakdown of how to interpret the technology output and answer the questions:

**(a) Confidence Interval Format:**

The technology output gives the 95% confidence interval as (12.800, 13.318).  In the "less than" symbol format, this is expressed as:

12.80 g/dL < μ < 13.32 g/dL

**(b) Point Estimate and Margin of Error:**

* **Best Point Estimate of μ:** The best point estimate of the population mean (μ) is the sample mean (x̄), which is given as x̄ = 13.059 g/dL.

* **Margin of Error:** The margin of error is half the width of the confidence interval.  You can calculate it as follows:

   Margin of Error = (Upper Limit - Lower Limit) / 2
   Margin of Error = (13.318 - 12.800) / 2
   Margin of Error = 0.518 / 2
   Margin of Error = 0.259 g/dL

**(c) Normality Assumption:**

Because the sample size is large (n = 100), the Central Limit Theorem applies.  The Central Limit Theorem states that the distribution of sample means will be approximately normal, *regardless* of the shape of the population distribution, as long as the sample size is sufficiently large (generally considered to be n ≥ 30).  Therefore, it is *not* necessary to confirm that the sample data appear to be from a normally distributed population when constructing this confidence interval.