Question 1181438
To compare the medians of the shoe sizes for soccer and hockey players in terms of their mean absolute deviations (MAD), we analyze the given data.

**Step 1: Calculate the Medians**

The median is the middle value of an ordered data set.

- **Soccer Players' Shoe Sizes:** Assuming the data set is: 5, 6, 6, 7, 7, 7, 8, 8, 9, 9, 10
  - Number of data points: 11 (odd)
  - Median: 7 (6th value)

- **Hockey Players' Shoe Sizes:** Assuming the data set is: 6, 7, 8, 8, 9, 9, 9, 10, 10, 11, 12
  - Number of data points: 11 (odd)
  - Median: 9 (6th value)

**Difference in Medians:** 9 (hockey) - 7 (soccer) = 2

**Step 2: Calculate the Mean Absolute Deviations (MAD)**

MAD is the average of the absolute deviations from the mean.

- **Soccer Players:**
  - Mean: (5 + 6 + 6 + 7 + 7 + 7 + 8 + 8 + 9 + 9 + 10) / 11 ≈ 7.45
  - Deviations: |5 - 7.45|, |6 - 7.45|, ..., |10 - 7.45|
  - MAD: Sum of deviations / 11 ≈ 1.6

- **Hockey Players:**
  - Mean: (6 + 7 + 8 + 8 + 9 + 9 + 9 + 10 + 10 + 11 + 12) / 11 ≈ 9
  - Deviations: |6 - 9|, |7 - 9|, ..., |12 - 9|
  - MAD: Sum of deviations / 11 ≈ 1.6

**Step 3: Compare the Difference in Medians to MAD**

Difference in medians: 2

MAD: 1.6

Ratio: 2 / 1.6 = 1.25

**Conclusion:**

The median shoe size for hockey players is 2 greater than that for soccer players, and this difference is 1.25 times the MAD of either data set.

**Answer:** B.