Question 1184067
Here's how to solve this problem:

**Let:**

* 'x' be the amount invested at 3.5% interest.
* 'y' be the amount invested at 4.5% interest.

**Set up the equations:**

* **Equation 1 (Total investment):** x + y = 1,000,000
* **Equation 2 (Total interest):** 0.035x + 0.045y = 43,000

**Solve the equations:**

One way to solve this is using substitution:

1. **Solve Equation 1 for x:** x = 1,000,000 - y

2. **Substitute this value of x into Equation 2:**
   0.035(1,000,000 - y) + 0.045y = 43,000

3. **Simplify and solve for y:**
   35,000 - 0.035y + 0.045y = 43,000
   0.01y = 8,000
   y = 800,000

4. **Substitute the value of y back into Equation 1 to find x:**
   x + 800,000 = 1,000,000
   x = 200,000

**Answer:**

* $200,000 was invested at 3.5% interest.
* $800,000 was invested at 4.5% interest.