Question 1184145
Here's how to calculate the probabilities:

**a. Both are good fruits:**

* **First pick:** There are 18 good fruits out of a total of 30 fruits.  The probability of picking a good fruit first is 18/30.
* **Second pick:** After picking one good fruit, there are now 17 good fruits left and a total of 29 fruits. The probability of picking another good fruit is 17/29.
* **Probability of both good:**  Multiply the probabilities of each pick: (18/30) * (17/29) = 306/870 = 51/145 ≈ 0.3517

**b. Both are bad fruits:**

* **First pick:** There are 12 bad fruits out of 30 total fruits. The probability of picking a bad fruit first is 12/30.
* **Second pick:** After picking one bad fruit, there are 11 bad fruits left and 29 total fruits. The probability of picking another bad fruit is 11/29.
* **Probability of both bad:** Multiply the probabilities: (12/30) * (11/29) = 132/870 = 22/145 ≈ 0.1517

**c. One is a good cashew and the other a bad mango:**

There are two ways this can happen: good cashew then bad mango, or bad mango then good cashew. We have to calculate the probability of each case and then add them together.

* **Good cashew then bad mango:**
    * Probability of good cashew first: 6/30
    * Probability of bad mango second: 6/29
    * Combined probability: (6/30) * (6/29) = 36/870 = 6/145 ≈ 0.0414

* **Bad mango then good cashew:**
    * Probability of bad mango first: 6/30
    * Probability of good cashew second: 6/29
    * Combined probability: (6/30) * (6/29) = 36/870 = 6/145 ≈ 0.0414

* **Total probability:** Add the probabilities of the two scenarios: (6/145) + (6/145) = 12/145 ≈ 0.0828