Question 1209693
To find the remainder when g(x) is divided by x - 1, we can use the Remainder Theorem. The Remainder Theorem states that if we divide a polynomial g(x) by (x - c), the remainder is g(c). In this case, we are dividing by x - 1, so c = 1.

First, let's simplify g(x) by combining like terms:
g(x) = (x^3 + 5x^3) + (-14x^2 - 20x^2) + (-67x + 7x) + (-90 - 135)
g(x) = 6x^3 - 34x^2 - 60x - 225

Now, we need to find g(1):
g(1) = 6(1)^3 - 34(1)^2 - 60(1) - 225
g(1) = 6 - 34 - 60 - 225
g(1) = -313

Therefore, the remainder when g(x) is divided by x - 1 is -313.

Final Answer: The final answer is $\boxed{-313}$