Question 1185349
Here are the probabilities you requested, calculated from the given table:

*   **Total People:** 3416

*   **In Favor:** 2013

*   **Against:** 1403

*   **Students:** 860

*   **Faculty:** 1251

*   **Administration:** 1305

*   **Students In Favor:** 652

*   **Students Against:** 208

*   **Faculty In Favor:** 665

*   **Faculty Against:** 586

*   **Admin In Favor:** 696

*   **Admin Against:** 609

1.  **Probability of being in favor:**

    P(In Favor) = (Number In Favor) / (Total People) = 2013 / 3416 ≈ 0.59

2.  **Probability of being a student and against:**

    P(Student and Against) = (Number of Students Against) / (Total People) = 208 / 3416 ≈ 0.06

3.  **Probability of being administration or against:**

    P(Admin or Against) = P(Admin) + P(Against) - P(Admin and Against)
    P(Admin) = 1305/3416 ≈ 0.38
    P(Against) = 1403/3416 ≈ 0.41
    P(Admin and Against) = 609/3416 ≈ 0.18

    P(Admin or Against) = 0.38 + 0.41 - 0.18 ≈ 0.61

4.  **Probability of being in favor and against:**

    This is impossible. A person cannot be both in favor and against at the same time.  Therefore, the probability is 0.

5.  **Probability of a faculty member being against:**

    P(Faculty Against | Faculty) = (Number of Faculty Against) / (Number of Faculty) = 586 / 1251 ≈ 0.47