Question 1209592
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{{{6x^2 + 10x = -2x^2 - 12x - 17}}}<br>
Put the equation in standard form for a polynomial:<br>
{{{8x^2+22x+17=0}}}<br>
Plug the numbers into the quadratic formula:<br>
{{{x = (-b +- sqrt( b^2-4*a*c ))/(2*a) }}}<br>
a=8, b=22, c=17<br>
{{{x = (-22 +- sqrt( 22^2-4*8*17 ))/(2*8) }}}<br>
{{{x = (-22 +- sqrt(484-544))/(16) }}}<br>
{{{x = (-22 +- i*sqrt(60))/(16) }}}<br>
Simplify as necessary....<br>