Question 1185696
Here's how to solve this problem:

**a. Finding the z-score:**

The z-score formula is:

z = (x - μ) / σ

Where:

*   x is the individual's blood pressure (112.8 mm Hg)
*   μ is the population mean blood pressure (119.3 mm Hg)
*   σ is the population standard deviation (13.6 mm Hg)

Plugging in the values:

z = (112.8 - 119.3) / 13.6
z = -6.5 / 13.6
z ≈ -0.48

So, the z-score for a woman with a blood pressure of 112.8 mm Hg is approximately **-0.48**.

**b. Finding the blood pressure:**

We can rearrange the z-score formula to solve for x (the blood pressure):

x = μ + zσ

We're given:

*   z = 2.15
*   μ = 119.3 mm Hg
*   σ = 13.6 mm Hg

Plugging in the values:

x = 119.3 + (2.15 * 13.6)
x = 119.3 + 29.24
x ≈ 148.5

So, the woman with a z-score of 2.15 had a systolic blood pressure reading of approximately **148.5 mm Hg**.