Question 1185738
Here's the breakdown of how to calculate the probabilities:

**(a) Probability of a careless driver under 25:**

*   Number of accidents caused by careless drivers under 25: 89
*   Total number of accidents: 944
*   Probability = (Number of careless drivers under 25) / (Total accidents) = 89 / 944 ≈ 0.0943  (Your provided answer of 0.5667 is incorrect.)

**(b) Probability of drinking and driving OR speeding:**

*   Number of accidents caused by drinking and driving: 340
*   Number of accidents caused by speeding: 296
*   Total accidents: 944
*   Probability = (Drinking and driving + Speeding) / Total = (340 + 296) / 944 = 636 / 944 ≈ 0.6737

**(c) Probability of drinking and driving OR a driver under 25:**

*   Number of accidents caused by drinking and driving: 340
*   Number of accidents involving drivers under 25: 535
*   Number of accidents caused by drinking and driving *and* a driver under 25: 286
*   Probability = (Drinking and driving + Under 25 - Both) / Total = (340 + 535 - 286) / 944 = 589 / 944 ≈ 0.6239

**(d) Probability the driver was at least 25 GIVEN speeding:**

*   Number of accidents caused by speeding: 296
*   Number of accidents caused by speeding and a driver 25 or above: 136
*   Probability = (Speeding and 25 or above) / (Total speeding) = 136 / 296 ≈ 0.4595

**(e) Probability of two careless driving accidents (without replacement):**

*   Probability of the first accident being caused by careless driving: 308 / 944
*   After one accident is chosen, there are 943 accidents left, and 307 are caused by careless driving.
*   Probability of the second accident being caused by careless driving: 307 / 943
*   Probability of both being caused by careless driving = (308 / 944) * (307 / 943) ≈ 0.1066