Question 1186021
Here's how to calculate the number of drums that can be filled:

**1. Convert psig to psia:**

* Tank pressure: 200 psig + 14.7 psia = 214.7 psia
* Drum pressure: 50 psig + 14.7 psia = 64.7 psia

**2. Convert temperatures to absolute Rankine:**

* Tank temperature: 85°F + 460 = 545°R
* Drum temperature: 80°F + 460 = 540°R

**3. Use the ideal gas law to find the mass of air in the tank:**

The ideal gas law is PV = mRT, where:

* P = pressure
* V = volume
* m = mass
* R = specific gas constant for air (1716 ft-lbf/slug-°R)
* T = temperature

Rearranging to solve for mass: m = PV / RT

m = (214.7 psia * 144 in²/ft² * 339.3 ft³) / (1716 ft-lbf/slug-°R * 545 °R)
m ≈ 4.79 slugs

**4. Use the ideal gas law again to find the volume the air will occupy at drum conditions:**

We'll use the same formula, but this time we're solving for V: V = mRT / P

V = (4.79 slugs * 1716 ft-lbf/slug-°R * 540 °R) / (64.7 psia * 144 in²/ft²)
V ≈ 2216.7 ft³

**5. Calculate the number of drums that can be filled:**

Number of drums = Volume of air at drum conditions / Volume per drum
Number of drums = 2216.7 ft³ / 1 ft³/drum
Number of drums ≈ 2217 drums

**Therefore, approximately 2217 drums can be filled.**