Question 1209551
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Your question seems a bit vague, but I'll try my best to answer. 
It sounds like you're given something like {{{sqrt(96)}}} and your teacher wants it simplified into the form {{{a*sqrt(b)}}} where a,b are integers and b > 0.


I'll provide two examples.


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Example 1
{{{sqrt(72) = sqrt(36*2)}}} See note below


{{{sqrt(72) = sqrt(36)*sqrt(2)}}} Use the rule sqrt(x*y) = sqrt(x)*sqrt(y) where x,y cannot be negative.


{{{sqrt(72) = sqrt(6^2)*sqrt(2)}}}


{{{sqrt(72) = 6*sqrt(2)}}} Use the rule sqrt(x^2) = x where x is nonnegative.


Note: I factored 72 so that one of the factors is a perfect square. 
We want this factor to be the largest perfect square possible.


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Example 2
{{{sqrt(245) = sqrt(49*5)}}}


{{{sqrt(245) = sqrt(49)*sqrt(5)}}}


{{{sqrt(245) = sqrt(7^2)*sqrt(5)}}}


{{{sqrt(245) = 7*sqrt(5)}}}
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