Question 17597
Let the number be x
8(x-3)=16
8x-24=16
8x=40
x=5
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3xyz-2xy+3xz-4x+5y for x=-3, y=-3, and z=-4
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3(-3)yz-2(-3)y+3(-3)z-4(-3)+5y [Substituting x]
-9yz+6y-9z+12+5y
-9(-3)z+6(-3)-9z+12+5(-3) [Substituting y]
27z-18-9z+12-15
27z-9z-6+15
18z+9
18(-4)+9 [substituting z]
-72+9
-63
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Hope this helps,
Prabhat