Question 1209538
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The top of a cone of height 10cm and base radius 7cm is cut off by a plane parallel to the base. 
If the distance between the plane and the base is 3cm, calculate the volume of the remaining object. [Take π = 22/7] 
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            Here is another,  more simple,  more straightforward 

            and computationally less extensive solving method.



<pre>
The volume of the original cone is  V = {{{(1/3)*pi*r^2*h}}} = {{{(1/3)*(22/7)*7^2*10}}} = 513.33333 cm^3.


The smaller cone is similar to the original one with the similarity coefficient {{{(10-3)/10}}} = {{{7/10}}} = 0.7.


Therefore, the volume of the smaller cone is  {{{0.7^3*V}}} = {{{0.7^3*513.33333}}} = 176.07533 cm^3.


The volume of the interest is the difference  513.33333 - 176.07533 = 337.26 cm^3.


<U>ANSWER<</U>.  The volume of the remaining object is  337.26 cm^3  (approximately).
</pre>

Solved in different way.