Question 1185951
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A firm has 550 employees; 380 of them have had at least some college education, and 412
of the employees underwent a vocational training program. Furthermore, 357 employees both are
college-educated and have had the vocational training. If an employee is chosen at random, what is
the probability that he or she is
college-educated or has had the training or both?
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            It is how to solve such problems:


Use the formula of addition for probabilities


    P(he or she is college-educated or has had the training or both) = 

       = {{{380/550}}} + {{{412/550}}} - {{{367/550}}} = {{{(380+412-367)/550}}} = {{{425/550}}} = {{{17/22}}}.    <U>ANSWER</U>
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Solved.