Question 1186210
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Architect Cristobal made $35,000 during the first year of his job. 
Each year, he received a 20% raise. What were his total earnings during the first ten years on the job? 
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<pre>
The sum of the first ten terms of the geometric progression with the first term of  {{{a[1]}}} = 35000
and the common ratio of  r = 1.2


    Sum = {{{a[1]*((r^10-1)/(r-1))}}} = {{{35000*((1.2^10-1)/(1.2-1))}}} = 908553.87.


<U>ANSWER</U>.  $908,553.87.
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Solved.