Question 1189635
Here's how to solve this problem:

1.  **Visualize the Triangle:** The hunter, basecamp, and bison form a triangle. The hunter is at point A, the basecamp is at point B, and the bison are at point C.  We know the distance AB (300m) and the angle ACB (60°). We need to find the distance AC.

2.  **Use the Law of Sines:** The Law of Sines is useful for solving triangles when you have an angle and its opposite side, and another angle or side.  In this case:

    AC / sin(B) = AB / sin(C)

    We don't know angle B yet, but we do know that the sum of angles in a triangle is 180. So, if we let angle A be represented by x, then x + B + 60 = 180, which simplifies to B = 120 - x. Since we don't know angle A, we can't use the law of sines yet. However, since we know that the triangle is a right triangle, we can use trigonometry.

3.  **Use Trigonometry:** Since the hunter is directly north of the basecamp, angle ABC is 90 degrees. This means we have a right triangle. We can use the tangent function to find the distance BC.

tan(60) = AB / BC

BC = AB / tan(60)

BC = 300 / √3

BC ≈ 173.21m

Now we can use the Pythagorean theorem to find AC

AC = √(AB^2 + BC^2)

AC = √(300^2 + 173.21^2)

AC = √(90000 + 30000)

AC = √(120000)

AC ≈ 346.41m

4.  **Calculate Required Speed:** The hunter has 2 minutes (120 seconds) to reach the bison.

    Speed = Distance / Time
    Speed = 346.41 m / 120 s
    Speed ≈ 2.89 m/s

**Answer:** The hunter must travel at approximately 2.89 m/s to reach the bison in time.