Question 116793
{{{x+1=sqrt(17-4x)}}}
{{{(x+1)^2=17-4x}}}
{{{x^2+2x+1=17-4x}}}
{{{x^2+6x-16=0}}}
{{{(x+8)(x-2)=0}}}
{{{highlight(x=-8)}}} and {{{highlight(x=2)}}}
Check your answers
{{{x+1=sqrt(17-4x)}}}
{{{-8+1=sqrt(17-4(-8))}}}
{{{-7=sqrt(17+32)}}}
{{{-7=sqrt(49)}}} 
{{{-7=-7}}} Remember the square root can be +7 or -7
True statement.
{{{x+1=sqrt(17-4x)}}}
{{{2+1=sqrt(17-4(2))}}}
{{{3=sqrt(17-8)}}}
{{{3=sqrt(9)}}}
{{{3=3}}}
True statement.
Good answers