Question 1192325
**1. Understand the Problem**

* We're given a normal distribution of rice bag weights.
* Mean weight (μ) = 5.05 kg
* Standard deviation (σ) = 0.02 kg
* We want to find the probability that a randomly selected bag weighs less than 5 kg.

**2. Calculate the Z-score**

* The Z-score tells us how many standard deviations a value is from the mean. 
* Formula: Z = (X - μ) / σ 
    * Where: 
        * X is the value we're interested in (5 kg)
        * μ is the mean 
        * σ is the standard deviation

* Calculation: Z = (5 - 5.05) / 0.02 = -0.25

**3. Find the Probability**

* We need to find the area under the standard normal distribution curve to the left of Z = -0.25. 
* You can use:
    * A Z-table: Look up the value corresponding to Z = -0.25 in a standard normal distribution table. 
    * Statistical software or calculator: Use functions like `norm.cdf()` in Python (scipy library) or similar functions in other tools.

* **Result:** The probability of a randomly selected bag weighing less than 5 kg is approximately **0.4013**.

**In summary:**

There's about a 40.13% chance that a randomly selected bag of rice from this mill will weigh less than 5 kg.