Question 1192376
**1. Define Variables**

* **D:** Internal diameter of the pipe (1 meter = 1000 mm) = 1000 mm
* **t:** Required wall thickness (in mm)
* **P:** Internal pressure = 750 kPa = 750,000 Pa
* **σ:** Allowable tensile stress = 140 MPa = 140,000,000 Pa

**2. Apply the Barlow Formula**

* The Barlow formula for calculating the minimum required wall thickness of a cylindrical pressure vessel is:

   t = (PD) / (2σ) 

   where:
       * t = wall thickness
       * P = internal pressure
       * D = internal diameter
       * σ = allowable tensile stress

**3. Calculate the Required Thickness**

* t = (750,000 Pa * 1000 mm) / (2 * 140,000,000 Pa)
* t = 750,000,000 / 280,000,000 
* t = 2.6786 mm

**Therefore, the required thickness of the steel pipe is approximately 2.68 mm.**