Question 1192542
.
<pre>
GOAL         0      1     2     3     4    5      > 5
p(X=x)       0.05   0.2   0.15  0.15  0.3  0.05   0.1
</pre>
find the probability that there would be total 5 goals in 2 matches?
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P (5 goals in 2 matches) = 0.05*0.05 + 0.2*0.3 + 0.15*0.15 + 0.15*0.15 + 0.3*0.2 + 0.05*0.05 = 0.17.    


<U>ANSWER</U>.  &nbsp;&nbsp;The probability that there would be a total of 5 goals in 2 matches is &nbsp;0.17, &nbsp;&nbsp;precisely &nbsp;&nbsp;(not approximately).