Question 1209472
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Find the sum of the proper divisors of 1 825 346.
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Prime decomposition is  1825346 = {{{2*97^3}}}.


The proper divisors are  97, 97^2, 97^3, 2, 2*97, 2*97^2.


The sum of all proper divisors is

    97 + 97^2 + 97^3 + 2 + 2*97 + 2*97^2 = 941193.    <U>ANSWER</U>
</pre>

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@greenestamps noticed that 1 is also a proper divisor and should be included in the sum.


It is true, I missed it, sorry.


The correct sum of all proper divisors is 


<pre>
    1 + 97 + 97^2 + 97^3 + 2 + 2*97 + 2*97^2 = 941194.
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