Question 1209464
The way the language works, if taking variation constant as k,
{{{x-3=ky^2}}}


Using the given data,
{{{5-3=k*2^2}}}

{{{2=4k}}}

{{{k=1/2}}}


So the model becomes {{{x-3=(1/2)y^2}}}


{{{x-3=(1/2)6^2}}}

{{{x-3=18}}}

{{{highlight(x=21)}}}