Question 1209426
The exercise is missing the logarithm of WHAT, to the base a.
A guess is you have this:
{{{log(a,2)=p}}} and {{{log(a,3)=q}}}.


Then you want to find what is {{{log(a,6)}}}.


{{{log(a,6)}}}
{{{log(a,2*3)}}}
{{{log(a,2)+log(a,3)}}}
and substituting using what is "given",
{{{p+q}}}.