Question 1209411
<pre>

{{{abs(x^2 - 30x - 1) = 30 + abs(6x - 2) + abs(x^2 - 20x - 4)}}}

Get 0 on the right:

{{{abs(x^2 - 30x - 1) - 30 - abs(6x - 2) - abs(x^2 - 20x - 4)=0}}}

Graph the left side in your TI-84 calculator. 

The "abs" feature is found this way: MATH NUM 1:abs(

Put it in Y1 like this:

abs(x^2 - 30x - 1) - 30 - abs(6x - 2) - abs(x^2 - 20x - 4)

Set the window Xmin=-10, Xmax=25, Ymin=-40, Ymax=60

Your graph will look something close to this:

{{{graph(400,400,-10,25,-40,60,abs(x^2 - 30x - 1) - 30 - abs(6x - 2) - abs(x^2 - 20x - 4))}}}

Use the zero feature of the calculator, and you'll find three solutions

The "zero" feature is found 2ND TRACE 2:zero

x = -7.25,   x = 7.75,  and x = 21.464225

Edwin</pre>