Question 1209384
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Label the points as A,B,C in any order you prefer.
A = (4,2)
B = (8,10)
C = (11,16)


Let's find the slope of line AB.
m = (y2 - y1)/(x2 - x1)
m = (10 - 2)/(8 - 4)
m = 8/4
m = 2


Do the same for line BC
m = (y2 - y1)/(x2 - x1)
m = (16 - 10)/(11 - 8)
m = 6/3
m = 2


Lines AB and BC have the same slope, so the three <font color=red>points are collinear</font>. 
Collinear points are on the same straight line. 
You can use graphing tools like <a href="https://www.desmos.com/calculator">Desmos</a> and <a href="https://www.geogebra.org/calculator">GeoGebra</a> to verify. 
The equation of the line that goes through all three points is y = 2x-6



Answer: <font color=red>True</font>
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