Question 1209361
.
How many values greater than 7000 can be formed using the digits 3, 5, 7, 8, 9 without repetition?
~~~~~~~~~~~~~~~~~~~~~~~


<pre>
There are two major options: the number can be any 4-digit, starting from any of the digits 7, 8, 9;

                       and   the number can be any 5-digit number.


In the first major option, there are 3 options for the 1st digit (7, 8 or 9);

                                     4 remaining options for the 2nd digit;

                                     3 remaining options for the 3rd digit;

                                     2 remaining options for the 4th digit;

                                     1 remaining option  for the 5th digit.


So, in the first major option, there are 3*4*3*2*1 = 72 possible different 4-digit numbers/values.


In the second major option, there are 5! = 120 possible different 5-digit numbers/values.


In all, there are 120 + 72 = 192 possible different numbers/values, satisfying imposed conditions.    <U>ANSWER</U>
</pre>

Solved.