Question 17588
Assuming that you mean {{{sqrt(x-2) -8=0}}}, let's just graph it and see where it crosses the x axis.  You can assume because of the square root that {{{x >= 2}}}.  That point is the value of x that is the solution for this equation:

{{{graph (600,300, 2,100,-10,10, sqrt(x-2)-8) }}}


The normal graph for x from -10 to 10 will NOT work here.  You will also have to use a fairly large value of x, like maybe up to x=100 to be able to see where the graph crosses the x axis.  It turns out that x= 66 is the value that works, so this is the solution.  X=66, and it checks also!


R^2 at SCC