Question 1194207
I can't directly access and process images, but based on the description of the image you linked (assuming it's the Venn diagram for the tennis club problem), I can help you solve it.

**Tennis Club Problem**

**Information:**

* There are 90 players in the tennis club.
* 23 are juniors (J).
* The rest are seniors (S).
* 34 seniors and 10 juniors are male (M).
* 8 juniors are left-handed (L), 5 of whom are male.
* There are 18 left-handed players in total, 4 of whom are female seniors.

**Task:**

Calculate the probability of various scenarios related to gender, age group, and handedness.

**Solution:**

**i) Venn Diagram Analysis**

Based on the information, populate the Venn diagram as follows:

* **Total:** 90 players
* **Juniors (J):** 23
    * **Male Juniors (J ∩ M):** 10
    * **Female Juniors (J ∩ M'):** 13
    * **Left-handed Juniors (J ∩ L):** 8
    * **Left-handed Female Juniors (J ∩ L ∩ M'):** 3
* **Seniors (S):** 67
    * **Male Seniors (S ∩ M):** 34
    * **Female Seniors (S ∩ M'):** 33
    * **Left-handed Seniors (S ∩ L):** 10
    * **Left-handed Female Seniors (S ∩ L ∩ M'):** 4

**ii) Probability Calculations**

**(a) Probability that a male player selected at random is left-handed:**

* P(L | M) = (Number of left-handed males) / (Total number of males)
* P(L | M) = (10 + 5) / (10 + 34) 
* P(L | M) = 15 / 44 
* P(L | M) ≈ 0.3409

**(b) Probability that a left-handed player selected at random is a female junior:**

* P(J ∩ M' | L) = (Number of left-handed female juniors) / (Total number of left-handed players)
* P(J ∩ M' | L) = 3 / 18 
* P(J ∩ M' | L) = 1/6 
* P(J ∩ M' | L) ≈ 0.1667

**(c) Probability that a player selected at random is either a junior or a female:**

* P(J ∪ M') = P(J) + P(M') - P(J ∩ M')
    * P(J) = 23/90
    * P(M') = (Number of females) / (Total players) = (13 + 33) / 90 = 46/90
    * P(J ∩ M') = (Number of female juniors) / (Total players) = 13/90 

* P(J ∪ M') = (23/90) + (46/90) - (13/90)
* P(J ∪ M') = 56/90 
* P(J ∪ M') ≈ 0.6222

**(d) Probability that a player selected at random is right-handed:**

* P(L') = 1 - P(L) 
* P(L') = 1 - (18/90) 
* P(L') = 72/90 
* P(L') = 0.8

**(e) Probability that a right-handed player selected at random is not a junior:**

* P(S | L') = (Number of right-handed seniors) / (Total number of right-handed players)
* P(S | L') = (34 + 33) / 72 
* P(S | L') = 67/72 
* P(S | L') ≈ 0.9306

**(f) Probability that a right-handed female player selected at random is a junior:**

* P(J | L' ∩ M') = (Number of right-handed female juniors) / (Total number of right-handed female players)
* P(J | L' ∩ M') = 13 / 33 
* P(J |