Question 1196060
To calculate the accumulated sum using **fractional compound interest**, we use the compound interest formula:  

\[
A = P \cdot (1 + r)^t
\]

Where:  
- \( A \) = Accumulated amount  
- \( P \) = Principal = \( R10,000 \)  
- \( r \) = Annual interest rate = \( 15.5\% = 0.155 \)  
- \( t \) = Time in years  

---

### **Step 1: Determine the Time Period (\( t \))**
1. Start date: **15 March 2012**  
2. End date: **1 July 2014**  

We calculate the total time in years:  
- From **15 March 2012** to **15 March 2014** is exactly 2 years.  
- From **15 March 2014** to **1 July 2014** is \( 3.5 \) months or \( \frac{3.5}{12} = 0.2917 \) years.  

Total time:  
\[
t = 2 + 0.2917 = 2.2917 \, \text{years}.
\]

---

### **Step 2: Apply the Compound Interest Formula**  
Substitute the values into the formula:  
\[
A = 10000 \cdot (1 + 0.155)^{2.2917}
\]

---

#### **Step 3: Break Down the Calculation**
1. Calculate \( (1 + 0.155) \):  
\[
1 + 0.155 = 1.155
\]

2. Calculate \( (1.155)^{2.2917} \):  
Using a calculator:  
\[
(1.155)^{2.2917} \approx 1.3840
\]

3. Calculate the accumulated amount \( A \):  
\[
A = 10000 \cdot 1.3840 = R13840.00
\]

---

### **Final Answer**
The accumulated sum on the fixed deposit is:  
\[
\boxed{R13,840.00}
\]