Question 1196639
**a) Probabilities for a Single Donor**

* **i) Has Type AB blood:** 
    * Probability = 100% - (46% + 42% + 9%) = 3%

* **ii) Has Type A or Type B blood:** 
    * Probability = 42% + 9% = 51%

* **iii) Is not Type O blood:** 
    * Probability = 100% - 46% = 54%

**b) Probabilities for Four Donors**

* **i) All are Type O:**
    * Probability = (0.46) * (0.46) * (0.46) * (0.46) = 0.46^4 ≈ 0.0457 (or 4.57%)

* **ii) None have Type AB blood:**
    * Probability of not having Type AB = 100% - 3% = 97% 
    * Probability that none have Type AB = (0.97) * (0.97) * (0.97) * (0.97) = 0.97^4 ≈ 0.8853 (or 88.53%)

* **iii) Not all are Type A:**
    * Probability that all are Type A = (0.42) * (0.42) * (0.42) * (0.42) = 0.42^4 ≈ 0.0311 (or 3.11%)
    * Probability that not all are Type A = 100% - 3.11% = 96.89%

* **iv) At least one person is Type B:**
    * Probability that none are Type B = (1 - 0.09)^4 = 0.6860
    * Probability that at least one person is Type B = 100% - 68.60% = 31.40%

**Note:** These calculations assume that the blood types of the donors are independent of each other.