Question 116627
<pre><font size = 4 color = "darkblue"><b>
                        {{{log(1/3,27)}}} = {{{x}}}

Use the definition of logs: {{{(1/3)^x}}} = {{{27}}}

Principle of exponents:    {{{(3/1)^(-x)}}} = {{{27}}}

Dispense with 1 denominator  {{{3^(-x)}}} = {{{27}}}

Write 27 as 3³               {{{3^(-x)}}} = {{{3^3}}}

Equate powers of 3               {{{-x}}} = {{{3}}}

Multiply both sides by -1         {{{x}}} = {{{-3}}}        

Edwin</pre>