Question 1209316
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Find the value of a for which there is exactly one real value of $x$ such that f(x) = a, 
where f(x) = x^2 + 4x - 31 + 4x^2 - 13x + 25.
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<pre>
                    <U>Step by step</U>


(1)  Reduce the given quadratic function f(x) to the standard form 

     f(x) = px^2 + qx + r  by combining like terms.



(2)  Complete the square and write your quadratic function in vertex form

        f(x) = {{{p(x-h)^2}}} + s.



(3)  The value of "s" in the last formula is your answer for "a".
</pre>

With given instructions, boldly go forward from the beginning to the end.


So, the value of  "a"  will be y-coordinate of the vertex.


Happy calculations (!)