Question 1209317
<pre>
Now if you want to change the problem so that f(0) = 0, not -5,
then:


       f(x+y) = x + f(y) + f(y^2) - y^2

Let x = -1 and y = 1

      f(-1+1) = -1 + f(1) + f(1^2) - 1^2

         f(0) = -1 + f(1) + f(1) - 1

            0 = 2f(1) - 2

            2 = 2f(1) 

         f(1) = 1

Edwin</pre>