Question 1209313
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If you are evaluating the log base 5 of 6.4, then 
{{{log(5,(6.4)) = (log((6.4)))/(log((5))) = matrix(1,2,1.153383,"approximately")}}} due to the change of base rule
You can use logs of any valid base with the change of base rule. 


This means you could say
{{{log(5,(6.4)) = (Ln(6.4))/(Ln(5)) = matrix(1,2,1.153383,"approximately")}}}
where Ln refers to the natural log



Or if you are trying to compute log(5^6.4) then use a calculator to get roughly 4.473408
This assumes the log is base 10. 
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