Question 1200742
Certainly, let's calculate the probability of all friends getting seats with even numbers given the provided information.

**1. Determine the number of even-numbered seats:**

* Total number of seats (n) = 33
* Number of even-numbered seats = n // 2 = 33 // 2 = 16 

**2. Calculate the probability for the remaining friends:**

* Number of friends who already have even seats (k) = 4
* Number of remaining friends = m - k = 6 - 4 = 2
* Remaining even-numbered seats = 16 - 4 = 12
* Remaining total seats = 33 - 4 = 29

* Probability of the first remaining friend getting an even seat: 12/29
* Probability of the second remaining friend getting an even seat: 11/28 

* Probability of both remaining friends getting even seats: (12/29) * (11/28) ≈ 0.162562

**Therefore, the probability that all friends will get seats with even numbers, given that 4 friends already have even seats, is approximately 0.162562.**