Question 1206684
We're given the following relationships:

1.  [y1 y2] = [x1 x2]A
2.  [z1 z2] = [x1 x2]B
3.  [z1 z2] = [y1 y2]C

We want to express C as a function of A and B. 

**Step 1: Substitute [y1 y2] in equation 3:**

From equation 1, we know that [y1 y2] = [x1 x2]A. Substitute this into equation 3:

[z1 z2] = ([x1 x2]A)C

**Step 2: Substitute [z1 z2] from equation 2:**

From equation 2, we know that [z1 z2] = [x1 x2]B. Substitute this into the previous equation:

[x1 x2]B = ([x1 x2]A)C

**Step 3: Simplify and Solve for C:**

Since [x1 x2] is a common factor on both sides, we can cancel it out:

B = AC

**Now, to isolate C, we can multiply both sides by the inverse of A (assuming A is invertible):**

A⁻¹B = C

**Therefore, C = A⁻¹B.**