Question 1209239
x and y the two numbers
{{{xy=-432}}} and {{{x+y=6}}}
Gives ,.... equation {{{x^2-6x-432=0}}}.


Better use in the form of 
{{{x(x-6)=432}}}.


Want two factors which differ by 6.

{{{x(x-6)=432}}}

{{{24*(18)=432}}}

{{{x=24}}}  and try to use this to find the other number.



{{{x+y=6}}}

{{{y=6-x}}}

{{{y=6-24}}}

{{{y=-18}}}

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Numbers are -18, and 24.