Question 1209238
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<pre>

First group of one student can be selected from 7 students in {{{C[7]^1}}} = 7 ways.

Second group of 3 students can be selected from remaining 7-1 = 6 students in {{{C{[6]^3}}} = {{{(6*5*4)/(1*2*3)}}} = 5*4 = 20 ways.


Third group of 3 students will consist of 3 remaining students, so there is only one choice to select this group.



So, the <U>ANSWER</U>  to the problem's question is this product

    in how many ways = 7*20 = 140 different ways.
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Solved.