Question 1209206
.
<pre>

Write equation as you read the problem

    -10x^2 + 160x - 430 = 50.


Collect all the terms in the left side

    -10x^2 + 160x - 430 - 50 = 0.


Combine like terms

    -10x^2 + 160x - 480 = 0.


Divide  all the terms by 10 (take off one zero symbol from all three terms)

    -x^2 + 16x - 48 = 0.


Change the sign in all terms on the left, for convenience

    x^2 - 16x + 48 = 0.


Factor left side

    (x-12)*(x-4) = 0.


The roots are 4 and 12.


So, x= 4 and x= 12 are two solutions to your problem.    <U>ANSWER</U>
</pre>

Solved.