Question 1209190
{{{system(3a^2-4y=-1, y=2a-1)}}}


{{{3a^2-4(2a-1)=-1}}}, substitution for y

{{{3a^2-8a+4=-1}}}

{{{3a^2-8a+5=0}}}

discriminant, just in case, {{{(-8)^2-4*3*5=64-60=4=2^2}}}

{{{a=(8+- sqrt(2^2))/6}}}

{{{a=(8+- 2)/6}}}

{{{system(a=1,or,5/3)}}}


If a=1 then y=1.
If a=5/3 then {{{y=2(5/3)-1=10/3-3/3=7/3}}};
so   (1,1) or ( 5/3, 7/3 ).


Check for any possible mistakes.