Question 1209190
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solve the simultaneous Equations 3a^2 - 4y = -1, 2a - y = 1
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From the second equation, express  y = 2a-1  and substitute it into first equation.
You will get

    3a^2 - 4(2a-1) = -1,

    3a^2 - 8a + 4 = -1,

    3a^2 - 8a + 5 = 0,


apply the quadratic formula

    {{{a[1,2]}}} = {{{(8 +- sqrt((-8)^2 - 4*3*5))/(2*3)}}} = {{{(8 +- 2)/6}}}.


So, there are two options for "a": they are

    a = {{{10/6}}} = {{{5/3}}}  and  a = 1.


Now find y for each value of "a", using y = 2a-1.
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From this point, can you complete on your own ?