Question 1209085
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Three runners, Dirk, Edith, and Foley all start at the same time for a 24 km race, 
and each of them runs at a constant speed. 
When Dirk finishes the race, Edith is 10 km behind, and Foley is 8 km behind {{{highlight(Edith)}}}. 
When Edith finishes the race, how far behind is Foley, in km?
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<pre>
From the problem, when Dirk completed the race, Edith ran  24-10 = 14 kilometers;
                                                Foley ran  14- 8 =  6 kilometers. 


From it, we conclude that Edith rate to Foley rate ratio is 14/6.


So, when Edith will complete 24 kilometers, the ratio of distances Edith and Foley run
will be the same 14/6.  It gives the proportion


    24          14
  ---------- = ----.
  Foley ran      6


From this proportion

    Foley run (when Edith finished) = {{{(24*6)/14}}} = {{{144/14}}} = {{{72/7}}} = 10.28571 kilometers.


Hence, when Edith finishes the rate, Foley is  24-10.2857 = 13.7143 kilometers behind (rounded value).
</pre>

Solved.