Question 1209027
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Find the lengths of the medians of the triangle whose vertices are A = (0,0), B =(6,0), and C = (4,4). 
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The median from A = (0,0) has the opposite end at D = (5,2).

Its length is  AD = {{{sqrt((5-0)^2 + (2-0)^2)}}} = {{{sqrt(29)}}}.



The median from B = (6,0) has the opposite end at E = (2,2).

Its length is  BE = {{{sqrt((2-6)^2 + (2-0)^2)}}} = {{{sqrt(4^2+2^2)}}} = {{{sqrt(20)}}} = {{{2*sqrt(5)}}}.



The median from C = (4,4) has the opposite end at F = (3,0).

Its length is  CF = {{{sqrt((4-3)^2+(4-0)^2)}}} = {{{sqrt(1 + 16)}}} = {{{sqrt(17)}}}.
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Solved in full.