Question 116584
I'll do the first two to show you how to solve these problems


Remember, the four quadrants are in these regions of the coordinate system:


{{{drawing(500,500,-6,6,-6,6,
graph(500,500,-6,6,-6,6,0),
locate(2,2,Quadrant I),
locate(-3,2,Quadrant II),
locate(-3,-2,Quadrant III),
locate(2,-2,Quadrant IV)
)}}}

#1


First plot the point (3,4)


Start at the origin (where the the x and y axis intersect)


Now move your pencil 3 units to the right

We move 3 units in this direction since the x-coordinate is 3 (its the first number of the pair)




{{{drawing(500,500,-6,6,-6,6,
grid(1),
blue(arc(0.5,0,1,2,0,180)),
blue(arc(1.5,0,1,2,0,180)),
blue(arc(2.5,0,1,2,0,180))
)}}}


Now go 4 units up

We move 4 units in this direction since the y-coordinate is 4 (its the second number of the pair)



{{{drawing(500,500,-6,6,-6,6,
grid(1),
blue(arc(0.5,0,1,2,0,180)),
blue(arc(1.5,0,1,2,0,180)),
blue(arc(2.5,0,1,2,0,180)),
green(arc(3,0.5,1,1,270,90)),
green(arc(3,1.5,1,1,270,90)),
green(arc(3,2.5,1,1,270,90)),
green(arc(3,3.5,1,1,270,90))
)}}}


Plot a point where the pencil lands


{{{drawing(500,500,-6,6,-6,6,
grid(1),
circle(3,4,0.08),
circle(3,4,0.10),
blue(arc(0.5,0,1,2,0,180)),
blue(arc(1.5,0,1,2,0,180)),
blue(arc(2.5,0,1,2,0,180)),
green(arc(3,0.5,1,1,270,90)),
green(arc(3,1.5,1,1,270,90)),
green(arc(3,2.5,1,1,270,90)),
green(arc(3,3.5,1,1,270,90))
)}}}


So here is the point (3,4)


{{{drawing(500,500,-6,6,-6,6,
grid(1),
circle(3,4,0.08),
circle(3,4,0.10)
)}}}


Now looking at the drawing of the quadrants, you can see that the point (3,4) is in the first quadrant


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#2

Now let's plot the point (5,-2)


Start at the origin (where the the x and y axis intersect)


Now move your pencil 5 units to the right

We move 5 units in this direction since the x-coordinate is 5 (its the first number of the pair)




{{{drawing(500,500,-6,6,-6,6,
grid(1),
blue(arc(0.5,0,1,2,180,0)),
blue(arc(1.5,0,1,2,180,0)),
blue(arc(2.5,0,1,2,180,0)),
blue(arc(3.5,0,1,2,180,0)),
blue(arc(4.5,0,1,2,180,0))
)}}}


Now go 2 units down

We move 2 units in this direction since the y-coordinate is -2 (its the second number of the pair)



{{{drawing(500,500,-6,6,-6,6,
grid(1),
blue(arc(0.5,0,1,2,180,0)),
blue(arc(1.5,0,1,2,180,0)),
blue(arc(2.5,0,1,2,180,0)),
blue(arc(3.5,0,1,2,180,0)),
blue(arc(4.5,0,1,2,180,0)),
green(arc(5,-0.5,1,1,270,90)),
green(arc(5,-1.5,1,1,270,90))
)}}}


Plot a point where the pencil lands


{{{drawing(500,500,-6,6,-6,6,
grid(1),
circle(5,-2,0.08),
circle(5,-2,0.10),
blue(arc(0.5,0,1,2,180,0)),
blue(arc(1.5,0,1,2,180,0)),
blue(arc(2.5,0,1,2,180,0)),
blue(arc(3.5,0,1,2,180,0)),
blue(arc(4.5,0,1,2,180,0)),
green(arc(5,-0.5,1,1,270,90)),
green(arc(5,-1.5,1,1,270,90))
)}}}


So here is the point (5,-2)


{{{drawing(500,500,-6,6,-6,6,
grid(1),
circle(5,-2,0.08),
circle(5,-2,0.10)
)}}}



Now looking at the drawing of the quadrants, you can see that the point (5,-2) is in the fourth quadrant