Question 1208984
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ABC is an equilateral triangle with sides of length 8 cm. Arc- AB, Arc-AC and Arc- BC are arcs 
of circles having their centres at C, B and A respectively. 
Find the total area of the non-shaded region of the diagram, in cm2.
https://ibb.co/pyVMjVQ
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<pre>
The non-shaded area consists of three disjoint congruent shapes.


For each shape, its area is 1/6 of the area of the circle with the radius of 8 cm
minus the area of the equilateral triangle with the side of 8 cm.


So, the non-shaded area is  


      {{{3*(1/6)*pi*8^2 - 3*8^2*(sqrt(3)/4)}}} =  {{{(1/2)*64*pi - 3*64*(sqrt(3)/4)}}} = {{{32*pi-3*16*sqrt(3)}}} = 


    = {{{32*3.14159-48*sqrt(3)}}} = 17.39244  cm^2  (rounded).    <U>ANSWER</U>
</pre>

Solved.