Question 1208929
<br>
The prescribed values for x are defined by<br>
{{{abs(x+1)<=3}}}
{{{-3<=x+1<=3}}}
{{{-4<=x<=2}}}<br>
The interval of x values is thus [-4,2].<br>
For all the values of x in that interval, x+5 is positive, so 1/(x+5) is positive and monotonically decreasing.  So the maximum value of 1/(x+5) on [-4,2] is at the left end of the interval and the minimum value is at the right end of the interval.<br>
ANSWERS:<br>
a = minimum value = 1/(2+5) = 1/7
b = maximum value = 1/(-4+5) = 1/1 = 1<br>