Question 1208831
<br>
Let the first number be x and the second be y.<br>
If he adds 2 to the first number and then multiplies the sum by three, the result is the second number: y=3(x+2)=3x+6<br>
If he subtracts 3 times the first number from the second number, the result is 8: y-3x=8 --> y=3x+8<br>
We now have two expressions for y in terms of x, so those two expressions must be equal: 3x+6 = 3x+8<br>
That equation clearly has no solutions.<br>
ANSWER: no solution<br>