Question 1208918
<pre>

It will be a success if the instructor chooses 3 females from the 5 in any of
C(5,3) ways and chooses 5 males from the 9 in any of C(9,5) ways --

out of the number of ways the instructor could possibly choose the 8, which is --

any 9 students out of the 5+9=14 students in any of C(14,8) ways:

{{{"C(5,3)"*"C(9,5)"/"C(14,8)"}}}{{{""=""}}}{{{(10*126)/3003}}}{{{""=""}}}{{{90/143}}}

about 42% of the time.

Edwin</pre>