Question 1208885
At the end of each year, Cannon gets 6% added to the balance.
If the balance at the beginning of a year is b, the interest earned is {{{b*6/100=b*0.06}}}.
That makes the end of the year balance {{{b*0.06+b=(0.06+1)b=1.06b}}} .
As that multiplying times {{{1.06}}} happens at the end of each year,
at the end of the 6th year the initial 25000 deposit has grown to
{{{25000*1.06^5=25000*1.3382255776=33455.64}}}(rounded to the nearest cent).
The second deposit would have grown to {{{25000*1.06^4}}}
The third deposit would have grown to {{{25000*1.06^3}}}
The fourth deposit would have grown to {{{25000*1.06^2}}}
The fifth deposit would have grown to {{{25000*1.06}}}
The total at the end of the sixth year will be
{{{25000*(1.06+1.06^2+1.06^3+1.06^4+1.06^5)=25000*(1.06^6-1.06)/0.06=149382.96}}}